There are 12 balls . One of them is of different weight as others(heaviier or lighter) and other 11 have the same weight
How to use a balance to determine the different ball in 3 times?
Please list your solution 作者: 海岸 時間: 2009-1-24 00:26
this question is stupid... any average 10 years old kid could answer this....
I just wanna point out that... the constraints in this problem are not tight,
that's mean if I add one more ball into your problem (13 balls instead of 12),
this problem is still solvable....
pls post in chinese next time.... 作者: 浪漫小家 時間: 2009-1-24 00:39
SO FUNNY 作者: 海岸 時間: 2009-1-24 11:18
Sure I can, but I'll skip on this one...
I've already pointed out that I could solve this problem with 13 balls,
by the way, do you think the 13 balls problem is unsolvable ???
if no, how could you still not believe that I am able to solve the 12 balls problem...
I could even prove that a 14 balls problem is unsolvable using simple mathematics... 作者: Ernie_A 時間: 2009-2-6 19:54
abcdefghijkl
abcd vs efgh
第一次:一樣重,即有8個真 abcdefgh unknown:ijkl
第二次:abc vs ijk, 一樣重即 l 假, ijk 重或輕即ijk假, 但已知假重或輕
第三次:i vs j, 一樣重即k假, i或j 輕重就睇第二次時假重或輕
第一次:不一樣,即abcd(假設為重邊), efgh(假設為輕邊)加ijkl四個真
第二次:abe vs cdg, 如abe重, 即a,b,g可能假, 如cdg重,即c,d,或e可能假 現假設abe重
第三次: a vs b, 一樣重則e假, a 或 b重則重為假 作者: Ernie_A 時間: 2009-2-7 11:47